.NET GENES

Hello all, Given the task at hand that your going to insert XML data into an XML column in SQL Server and you encounter this error "XML parsing: line 1, character 38, unable to switch the encoding", it seems the insertion of XML data failed due to this line here: <?xml version="1.0" encoding="utf-8" ?> . After doing some research, I found a tutorial on how to avoid unicode issues when inserting XML data into an XML column in SQL Server which is the basis of the solution. I just change the Encoding of the stream to UTF8 to match the encoding of the XML file. using (SqlConnection con = new SqlConnection(ConfigurationManager.ConnectionStrings[ "DefaultConnection" ].ConnectionString)) { SqlCommand command = new SqlCommand( "Insert into XMLTable(name, xmlData) values (@name, @xmlData)" , con); con.Open(); string xmlFile = File.ReadAllText(location); using (MemoryStream stream = new MemoryStream()) { using (StreamWrite

Hello, In this tutorial, I will demonstrate seeding roles and users to an existing database in an ASP.NET MVC 5 application using Identity framework. For simplicity, I will use a Northwind. This database doesn't have membership tables at all. To begin with, accomplish the steps below: 1. Create an ASP.NET MVC application and then change web.config connectionStrings element to connect to an existing database (Northwind as my example). 2. Under Package Manager Console type PM> Enable-Migrations 3. Under Package Manager Console type PM> Add-Migration ASPMembership * This will create a file Timespan_ASPMembership.cs inside Migrations folder with scripts to create Membership Tables such as AspNetUsers, AspNetRoles and etc. 4. Under Package Manager Console type PM> Update-Database * This will add membership tables to Northwind database. 5. To seed Roles and Users, create a class SeedRolesAndUsers.cs inside Models folder. This class referenc

Hello, When I started creating an ASP.NET MVC application in VB.NET and decided to add Membership tables using the Enable-Migrations command in Package Manager Console, I encountered this error 'The term 'Enable-Migrations' is not recognized as the name of a cmdlet'. In C#, I haven't encountered this issue. So, what I did was to Rebuild the project, and then restart Visual Studio IDE. Eureka,the problem was fixed. :-) Cheers! :)

Hi, There was a question on the forums on how to set the background color of DataGridCell or DataGridRow using XAML without code. I always thought that the solution will be to use code using IValueConverter. After doing some searching on MSDN and google, the answer is straightforward using Triggers. To set the color of DataGridRow, you set the DataGrid.CellStyle just below the DataGrid markup. <DataGrid Grid.Row= "0" Grid.Column= "0" AutoGenerateColumns= "False" CanUserAddRows= "False" Name= "dgStudents" > <DataGrid.CellStyle> <Style TargetType= "{x:Type DataGridCell}" > <Style.Triggers> <DataTrigger Binding= "{Binding Age}" Value= "28" > <Setter Property= "Background" Value= "Gray" ></Setter> </DataTrigger> </Style.Triggers> </Style> </DataGrid.CellStyle> <DataGrid.Columns>

Hello, I did some research on how to use enums as model for DropDownListFor() for a current application and will format it with Bootstrap classes. For ASP.NET MVC 4, it does not have that kind of helper yet. Luckily, I found an article here Creating a DropDownList helper for enums which supports enums as data source. However, it does not have an argument where in you can pass a boostrap class such as form-control. To achieve the desired output, all you need to do is modify the helper and add another parameter for html attributes which will then be used by the DropDownListFor(). public static MvcHtmlString EnumDropDownListFor<TModel, TEnum>( this HtmlHelper<TModel> htmlHelper, Expression<Func<TModel, TEnum>> expression, object htmlAttributes) { ModelMetadata metadata = ModelMetadata.FromLambdaExpression(expression, htmlHelper.ViewData); IEnumerable<TEnum> values = Enum.GetValues( typeof (TEnum)).Cast<TEnum>(); IEnumerable<SelectListIte

Hi, In this tutorial, I will present three ways on model binding with the @Html.ListBoxFor() helper using a ViewModel class and a simple model class. The Index view below has three @Html.ListBoxFor() controls inside a form that will be populated with different ways using MultiSelectList class, List<SelectListItem> , and IEnumerable<CountryInfo> . @using (Html.BeginForm("Index", "Home", FormMethod.Post)) { <div class= "form-group" > <div class= "form-group" > @Html.ListBoxFor(x => x.SelectedPhoneNumbers, Model.phoneNumbers, new { @class = "form-control " }) </div> <div class= "form-group" > @Html.ListBoxFor(x => x.SelectedItemIds, Model.Items, new { @class = "form-control " }) </div> <div class= "form-group" > @Html.ListBoxFor(x => x.Country.SelectedCountry, new MultiSelectList(Model.Country.Countries, "Code", "T

Hello, Here's a simple demonstration on how to parse JSON data using .NET's JavaScriptSerializer class. Given the sample JSON data below: { "catalog": { "book": [ { "id": "bk101" , "author": "Gambardella, Matthew" , "title": "XML Developer's Guide" , "genre": "Computer" , "price": "44.95" , "publish_date": "2000-10-01" , "description": "An in-depth look at creating applications with XML." }, { "id": "bk102" , "author": "Ralls, Kim" , "title": "Midnight Rain" , "genre": "Fantasy" , "price": "5.95" , "publish_date": "2000-12-16" , "description": &q

Hello, Normally, you submit client-side data to a controller action via @Html.BeginForm(), then perform processing statements and lastly invoke the return View(); statement inside the controller action which will redirect you to the view which basically works. However, in a scenario where-in you will post data to a controller action using jQuery Control Event such as Button Click , the return View() statement in the controller action won't redirect to the specified view given the sample controller action below. [HttpPost] public ActionResult UpdatedEmpTrainings( string empId) { _context = new EmployeeEntities(); model = new List<EmployeeTrainingsViewModel>(); model = ( from emp_trainings in _context.EmployeeTrainings.AsEnumerable() join training in _context.Trainings.AsEnumerable() on emp_trainings.TrainingID equals training.TrainingID where emp_trainings.EmployeeID == Convert.ToInt32(empId) select new EmployeeTrainingsViewModel {

Hello, There was a question in the forums on how to add a line separator in every method written in Visual Studio 2013 C# IDE. Well, there's a plugin for Visual Studio called Productivity Power Tools 2013 which you can download and install. After installing it, then proceed to making changes to your IDE. To show line separator in your Visual Studio 2013 IDE, perform the steps below: Click on Tools Menu -> Options -> Productivity Power Tools -> Other Extensions -> Show a separator between methods in the Editor Screenshot: Note: Make sure to restart Visual Studio to affect those changes. Reference: Visual Studio 2013 Goodies